If the stuntwoman in Example 10 were to jump off the cliff,
what would be her final speed as she landed on a large, air-filled cushion lying on the ground?
$v=28\ \mathrm{\displaystyle \frac{m}{s}}$
The gravitational potential energy would be transformed into kinetic energy. So
$$U\to K$$
$$U\to \frac{1}{2}mv^2$$
$$v=\sqrt{\frac{2\cdot U}{m}}$$
$$v=\sqrt{\frac{2(24,000\ \mathrm{J})}{60\ \mathrm{kg}}}$$
$$v=28\ \mathrm{\frac{m}{s}}$$